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5x-3x^2=-8-6x
We move all terms to the left:
5x-3x^2-(-8-6x)=0
We add all the numbers together, and all the variables
-3x^2+5x-(-6x-8)=0
We get rid of parentheses
-3x^2+5x+6x+8=0
We add all the numbers together, and all the variables
-3x^2+11x+8=0
a = -3; b = 11; c = +8;
Δ = b2-4ac
Δ = 112-4·(-3)·8
Δ = 217
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{217}}{2*-3}=\frac{-11-\sqrt{217}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{217}}{2*-3}=\frac{-11+\sqrt{217}}{-6} $
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